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[WebApiUtils] Added save uploaded file

develop
Robin Thoni 9 gadus atpakaļ
vecāks
revīzija
51f5b3c0cb
1 mainītis faili ar 52 papildinājumiem un 1 dzēšanām
  1. 52
    1
      WebApiUtils/BusinessManager/BMRHandler.cs

+ 52
- 1
WebApiUtils/BusinessManager/BMRHandler.cs Parādīt failu

@@ -1,5 +1,11 @@
1
-using System.Net;
1
+using System;
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+using System.Collections.Generic;
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+using System.IO;
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+using System.Linq;
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+using System.Net;
2 6
 using System.Net.Http;
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+using System.Threading;
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+using System.Threading.Tasks;
3 9
 using System.Web.Http;
4 10
 using iiie.Logs.DataAccess;
5 11
 using iiie.Logs.DBO;
@@ -65,5 +71,50 @@ namespace iiie.WebApiUtils.BusinessManager
65 71
             var msg = Request.CreateErrorResponse(ResultStatusToHttp(result.Status), OpResultToString(result));
66 72
             throw new HttpResponseException(msg);
67 73
         }
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+
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+        /// <summary>
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+        /// Save the uploaded file to the temp dir
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+        /// </summary>
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+        /// <returns>The file path</returns>
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+        public async Task<OpResult<string>> SaveFileToTemp()
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+        {
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+            if (!Request.Content.IsMimeMultipartContent())
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+            {
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+                return OpResult<string>.Error(ResultStatus.InputError, "Bad content type", "");
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+            }
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+            IEnumerable<HttpContent> parts = null;
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+            try
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+            {
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+                Task.Factory.StartNew(() => parts = Request.Content.ReadAsMultipartAsync().Result.Contents,
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+                        CancellationToken.None, TaskCreationOptions.LongRunning, TaskScheduler.Default).Wait();
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+            }
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+            catch (Exception e)
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+            {
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+                return OpResult<string>.Error(ResultStatus.InputError, e, "Failed to read uploaded file");
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+            }
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+            HttpContent file = parts.FirstOrDefault();
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+            if (file == null)
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+            {
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+                return OpResult<string>.Error(ResultStatus.InputError, "No uploaded file", "");
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+            }
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+            try
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+            {
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+                var path = Path.GetTempFileName();
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+                using (var memoryStream = new MemoryStream(await file.ReadAsByteArrayAsync()))
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+                {
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+                    using (var streamWriter = new FileStream(path, FileMode.OpenOrCreate))
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+                    {
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+                        memoryStream.WriteTo(streamWriter);
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+                        memoryStream.Close();
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+                        streamWriter.Close();
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+                    }
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+                }
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+                return OpResult<string>.Ok(path);
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+            }
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+            catch (Exception e)
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+            {
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+                return OpResult<string>.Error(ResultStatus.InputError, e, "Failed to write uploaded file");
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+            }
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+        }
68 119
     }
69 120
 }

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