123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142 |
- /*
- * Copyright (C) 2012 Michael Brown <mbrown@fensystems.co.uk>.
- *
- * This program is free software; you can redistribute it and/or
- * modify it under the terms of the GNU General Public License as
- * published by the Free Software Foundation; either version 2 of the
- * License, or any later version.
- *
- * This program is distributed in the hope that it will be useful, but
- * WITHOUT ANY WARRANTY; without even the implied warranty of
- * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
- * General Public License for more details.
- *
- * You should have received a copy of the GNU General Public License
- * along with this program; if not, write to the Free Software
- * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
- * 02110-1301, USA.
- *
- * You can also choose to distribute this program under the terms of
- * the Unmodified Binary Distribution Licence (as given in the file
- * COPYING.UBDL), provided that you have satisfied its requirements.
- */
-
- FILE_LICENCE ( GPL2_OR_LATER_OR_UBDL );
-
- #include <time.h>
-
- /** @file
- *
- * Date and time
- *
- * POSIX:2008 section 4.15 defines "seconds since the Epoch" as an
- * abstract measure approximating the number of seconds that have
- * elapsed since the Epoch, excluding leap seconds. The formula given
- * is
- *
- * tm_sec + tm_min*60 + tm_hour*3600 + tm_yday*86400 +
- * (tm_year-70)*31536000 + ((tm_year-69)/4)*86400 -
- * ((tm_year-1)/100)*86400 + ((tm_year+299)/400)*86400
- *
- * This calculation assumes that leap years occur in each year that is
- * either divisible by 4 but not divisible by 100, or is divisible by
- * 400.
- */
-
- /** Days of week (for debugging) */
- static const char *weekdays[] = {
- "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"
- };
-
- /**
- * Determine whether or not year is a leap year
- *
- * @v tm_year Years since 1900
- * @v is_leap_year Year is a leap year
- */
- static int is_leap_year ( int tm_year ) {
- int leap_year = 0;
-
- if ( ( tm_year % 4 ) == 0 )
- leap_year = 1;
- if ( ( tm_year % 100 ) == 0 )
- leap_year = 0;
- if ( ( tm_year % 400 ) == 100 )
- leap_year = 1;
-
- return leap_year;
- }
-
- /**
- * Calculate number of leap years since 1900
- *
- * @v tm_year Years since 1900
- * @v num_leap_years Number of leap years
- */
- static int leap_years_to_end ( int tm_year ) {
- int leap_years = 0;
-
- leap_years += ( tm_year / 4 );
- leap_years -= ( tm_year / 100 );
- leap_years += ( ( tm_year + 300 ) / 400 );
-
- return leap_years;
- }
-
- /**
- * Calculate day of week
- *
- * @v tm_year Years since 1900
- * @v tm_mon Month of year [0,11]
- * @v tm_day Day of month [1,31]
- */
- static int day_of_week ( int tm_year, int tm_mon, int tm_mday ) {
- static const uint8_t offset[12] =
- { 1, 4, 3, 6, 1, 4, 6, 2, 5, 0, 3, 5 };
- int pseudo_year = tm_year;
-
- if ( tm_mon < 2 )
- pseudo_year--;
- return ( ( pseudo_year + leap_years_to_end ( pseudo_year ) +
- offset[tm_mon] + tm_mday ) % 7 );
- }
-
- /** Days from start of year until start of months (in non-leap years) */
- static const uint16_t days_to_month_start[] =
- { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 };
-
- /**
- * Calculate seconds since the Epoch
- *
- * @v tm Broken-down time
- * @ret time Seconds since the Epoch
- */
- time_t mktime ( struct tm *tm ) {
- int days_since_epoch;
- int seconds_since_day;
- time_t seconds;
-
- /* Calculate day of year */
- tm->tm_yday = ( ( tm->tm_mday - 1 ) +
- days_to_month_start[ tm->tm_mon ] );
- if ( ( tm->tm_mon >= 2 ) && is_leap_year ( tm->tm_year ) )
- tm->tm_yday++;
-
- /* Calculate day of week */
- tm->tm_wday = day_of_week ( tm->tm_year, tm->tm_mon, tm->tm_mday );
-
- /* Calculate seconds since the Epoch */
- days_since_epoch = ( tm->tm_yday + ( 365 * tm->tm_year ) - 25567 +
- leap_years_to_end ( tm->tm_year - 1 ) );
- seconds_since_day =
- ( ( ( ( tm->tm_hour * 60 ) + tm->tm_min ) * 60 ) + tm->tm_sec );
- seconds = ( ( ( ( time_t ) days_since_epoch ) * ( ( time_t ) 86400 ) ) +
- seconds_since_day );
-
- DBGC ( &weekdays, "TIME %04d-%02d-%02d %02d:%02d:%02d => %lld (%s, "
- "day %d)\n", ( tm->tm_year + 1900 ), ( tm->tm_mon + 1 ),
- tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec, seconds,
- weekdays[ tm->tm_wday ], tm->tm_yday );
-
- return seconds;
- }
|