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+/*
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+ * Copyright (C) 2012 Michael Brown <mbrown@fensystems.co.uk>.
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+ *
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+ * This program is free software; you can redistribute it and/or
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+ * modify it under the terms of the GNU General Public License as
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+ * published by the Free Software Foundation; either version 2 of the
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+ * License, or any later version.
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+ *
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+ * This program is distributed in the hope that it will be useful, but
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+ * WITHOUT ANY WARRANTY; without even the implied warranty of
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+ * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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+ * General Public License for more details.
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+ *
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+ * You should have received a copy of the GNU General Public License
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+ * along with this program; if not, write to the Free Software
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+ * Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA.
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+ */
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+
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+FILE_LICENCE ( GPL2_OR_LATER );
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+
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+#include <time.h>
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+
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+/** @file
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+ *
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+ * Date and time
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+ *
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+ * POSIX:2008 section 4.15 defines "seconds since the Epoch" as an
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+ * abstract measure approximating the number of seconds that have
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+ * elapsed since the Epoch, excluding leap seconds. The formula given
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+ * is
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+ *
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+ * tm_sec + tm_min*60 + tm_hour*3600 + tm_yday*86400 +
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+ * (tm_year-70)*31536000 + ((tm_year-69)/4)*86400 -
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+ * ((tm_year-1)/100)*86400 + ((tm_year+299)/400)*86400
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+ *
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+ * This calculation assumes that leap years occur in each year that is
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+ * either divisible by 4 but not divisible by 100, or is divisible by
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+ * 400.
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+ */
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+
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+/** Days of week (for debugging) */
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+static const char *weekdays[] = {
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+ "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"
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+};
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+
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+/**
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+ * Determine whether or not year is a leap year
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+ *
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+ * @v tm_year Years since 1900
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+ * @v is_leap_year Year is a leap year
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+ */
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+static int is_leap_year ( int tm_year ) {
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+ int leap_year = 0;
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+
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+ if ( ( tm_year % 4 ) == 0 )
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+ leap_year = 1;
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+ if ( ( tm_year % 100 ) == 0 )
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+ leap_year = 0;
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+ if ( ( tm_year % 400 ) == 100 )
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+ leap_year = 1;
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+
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+ return leap_year;
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+}
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+
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+/**
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+ * Calculate number of leap years since 1900
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+ *
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+ * @v tm_year Years since 1900
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+ * @v num_leap_years Number of leap years
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+ */
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+static int leap_years_to_end ( int tm_year ) {
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+ int leap_years = 0;
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+
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+ leap_years += ( tm_year / 4 );
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+ leap_years -= ( tm_year / 100 );
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+ leap_years += ( ( tm_year + 300 ) / 400 );
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+
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+ return leap_years;
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+}
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+
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+/**
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+ * Calculate day of week
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+ *
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+ * @v tm_year Years since 1900
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+ * @v tm_mon Month of year [0,11]
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+ * @v tm_day Day of month [1,31]
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+ */
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+static int day_of_week ( int tm_year, int tm_mon, int tm_mday ) {
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+ static const uint8_t offset[12] =
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+ { 1, 4, 3, 6, 1, 4, 6, 2, 5, 0, 3, 5 };
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+ int pseudo_year = tm_year;
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+
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+ if ( tm_mon < 2 )
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+ pseudo_year--;
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+ return ( ( pseudo_year + leap_years_to_end ( pseudo_year ) +
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+ offset[tm_mon] + tm_mday ) % 7 );
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+}
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+
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+/** Days from start of year until start of months (in non-leap years) */
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+static const uint16_t days_to_month_start[] =
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+ { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 };
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+
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+/**
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+ * Calculate seconds since the Epoch
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+ *
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+ * @v tm Broken-down time
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+ * @ret time Seconds since the Epoch
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+ */
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+time_t mktime ( struct tm *tm ) {
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+ int days_since_epoch;
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+ int seconds_since_day;
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+ time_t seconds;
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+
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+ /* Calculate day of year */
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+ tm->tm_yday = ( ( tm->tm_mday - 1 ) +
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+ days_to_month_start[ tm->tm_mon ] );
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+ if ( ( tm->tm_mon >= 2 ) && is_leap_year ( tm->tm_year ) )
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+ tm->tm_yday++;
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+
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+ /* Calculate day of week */
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+ tm->tm_wday = day_of_week ( tm->tm_year, tm->tm_mon, tm->tm_mday );
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+
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+ /* Calculate seconds since the Epoch */
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+ days_since_epoch = ( tm->tm_yday + ( 365 * tm->tm_year ) - 25567 +
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+ leap_years_to_end ( tm->tm_year - 1 ) );
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+ seconds_since_day =
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+ ( ( ( ( tm->tm_hour * 60 ) + tm->tm_min ) * 60 ) + tm->tm_sec );
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+ seconds = ( ( ( ( time_t ) days_since_epoch ) * ( ( time_t ) 86400 ) ) +
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+ seconds_since_day );
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+
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+ DBGC ( &weekdays, "TIME %04d-%02d-%02d %02d:%02d:%02d => %lld (%s, "
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+ "day %d)\n", ( tm->tm_year + 1900 ), ( tm->tm_mon + 1 ),
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+ tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec, seconds,
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+ weekdays[ tm->tm_wday ], tm->tm_yday );
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+
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+ return seconds;
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+}
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